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T2 Ship Invention and Decryptors
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Malcom Dax
Sebiestor Tribe
Minmatar Republic
#1 - 2011-11-22 12:16:19 UTC
First off, sorry for asking about this, I know it gets asked a lot but I've read a number of different threads on this and am now very confused on the matter.

When inventing T2 ships using a decryptor that gives me +2 runs (Operation Handbooks for example) and a 1-run T1 BPC I get 2-runs on the T2 BPC; I was expecting 3. I'm aware that the number of runs on the T1 BPC effects the number of runs on the T2 BPC but had been led to believe, by some forum posts and some online invention calculators, that this was not the case for ships. Hence expecting 3 runs on the T2 BPC.

Question: For ship invention, if I want 3 runs on the T2 BPC I still have to use a max-run blueprint right?

I've also read somewhere that the formula below was not correct as far as ship invention BPC runs was concerned.

Invention Output Runs = MIN(MAX(ROUND_DOWN( (Input_T1_BPC_Runs / T1_Max_Runs_Per_Blueprint_Copy) * (T2_Max_Runs_Per_Blueprint_Copy / 10) + Decryptor_Runs_Bonus), 1), T2_Max_Runs_Per_Blueprint_Copy)

Question: Is the above correct for all types of invention?

Thanks in advance for any answers to these two questions. Getting my head straight on these will help me sort out my profit/loss calculations, which are obviously [censored]-up by getting 1 less run than I was expecting.

.
Lutz Major
Austriae Est Imperare Orbi Universo
#2 - 2011-11-22 12:20:36 UTC  |  Edited by: Lutz Major
Q1) Yes.
Q2) Yes.

edit: and to elaborate a bit more:
Invention Output Runs = MIN(MAX(ROUND_DOWN((Input_T1_BPC_Runs / T1_Max_Runs_Per_Blueprint_Copy) * (T2_Max_Runs_Per_Blueprint_Copy / 10) + Decryptor_Runs_Bonus), 1), T2_Max_Runs_Per_Blueprint_Copy)

Inventing Golem w/ 1 run:
= MIN(MAX(ROUND_DOWN((1 / 10) * (10 / 10) + 2), 1), 10)
= MIN(MAX(ROUND_DOWN(0.10 * 1 + 2), 1), 10)
= MIN(MAX(ROUND_DOWN(0.10 + 2), 1), 10)
= MIN(MAX(ROUND_DOWN(2.10), 1), 10)
= MIN(MAX(2, 1), 10)
= MIN(2, 10)
= 2


Inventing Golem w/ 9 runs:
= MIN(MAX(ROUND_DOWN((9 / 10) * (10 / 10) + 2), 1), 10)
= MIN(MAX(ROUND_DOWN(0.90 * 1 + 2), 1), 10)
= MIN(MAX(ROUND_DOWN(0.90 + 2), 1), 10)
= MIN(MAX(ROUND_DOWN(2.90), 1), 10)
= MIN(MAX(2, 1), 10)
= MIN(2, 10)
= 2


Inventing Golem w/ 10 runs
= MIN(MAX(ROUND_DOWN((10 / 10) * (10 / 10) + 2), 1), 10)
= MIN(MAX(ROUND_DOWN(1 * 1 + 2), 1), 10)
= MIN(MAX(ROUND_DOWN(1 + 2), 1), 10)
= MIN(MAX(ROUND_DOWN(3), 1), 10)
= MIN(MAX(3, 1), 10)
= MIN(3, 10)
= 3
Malcom Dax
Sebiestor Tribe
Minmatar Republic
#3 - 2011-11-22 13:17:29 UTC
Thanks. That's a very good set of examples.

.
Tau Cabalander
Retirement Retreat
Working Stiffs
#4 - 2011-11-22 20:22:19 UTC  |  Edited by: Tau Cabalander
EVElopedia - Invention wrote:
The number of runs on a BPC from a successful Invention is proportional to the number of runs on the input BPC divided by the maximum runs on the input BPC, which is then multiplied by 1/10 of the maximum runs of the output BPC type. The complete formula is detailed below.

This ratio has particular consequences for ships and rigs, where the Max Runs Per Copy on the Tech 2 blueprints for these items is 10, which works out to a base maximum runs of 1. Due to this base maximum of 1, any number of runs less than maximum for the input will get rounded off to zero after the decryptor run modifier is added and before the minimum is applied.

Thus, for optimal number of output runs when inventing ships or rigs, use:

* 1-run input BPCs when not using a decryptor, or using a decryptor that does not modify the number of runs

* Max Run input BPCs when using a decryptor that modifies the number of runs

When inventing modules, ammunition and other non-ship or rig items, its is worthwhile to use maximum run input BPCs to get a T2 BPC with most possible runs.

http://wiki.eveonline.com/en/wiki/Invention#Invention_BPC_Runs