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T2 BPC number of runs from T1 BPC.

Author
Victoria Sin
Doomheim
#1 - 2013-09-16 13:11:33 UTC
Max run module BPC's, usually 300 run, produce a 10 run T2 BPC with invention (without using a decryptor). How can I answer the question, "how many runs will my T2 BPC have if I invent it with an N run T1 BPC", for any inventable item in the database?

Not too sure which parameters I need to look at in the DB and what the calculation is here. Anyone know? Also, is it relatively straightforward to add in decryptor properties to this?
Steve Ronuken
Fuzzwork Enterprises
Vote Steve Ronuken for CSM
#2 - 2013-09-16 13:58:42 UTC  |  Edited by: Steve Ronuken
min(max(round((inputT1/T1 Max)*(T2 max/10)),1)+decryptor bonus,T2 max)


input t1: how many runs you have on the BPC
t1 max: The max run count from invTypeBlueprints, for the T1 blueprint. maxProductionLimit
T2 max: the max run count from invtypeBlueprints, for the t2 blueprint. maxProductionLimit
Decryptor bonus: from attribute 1124 of the decryptor

http://pastebin.com/Ugq4NC0q if you want the relevant decryptors for a blueprint





https://www.fuzzwork.co.uk/2013/05/23/manufacturing-201-tech-2/

Woo! CSM XI!

Fuzzwork Enterprises

Twitter: @fuzzysteve on Twitter

Victoria Sin
Doomheim
#3 - 2013-09-16 14:44:00 UTC
Steve Ronuken wrote:
min(max(round((inputT1/T1 Max)*(T2 max/10)),1)+decryptor bonus,T2 max)


input t1: how many runs you have on the BPC
t1 max: The max run count from invTypeBlueprints, for the T1 blueprint. maxProductionLimit
T2 max: the max run count from invtypeBlueprints, for the t2 blueprint. maxProductionLimit
Decryptor bonus: from attribute 1124 of the decryptor

http://pastebin.com/Ugq4NC0q if you want the relevant decryptors for a blueprint





https://www.fuzzwork.co.uk/2013/05/23/manufacturing-201-tech-2/


Wonderful! Thanks. Can't wait to show off my efforts when I'm done Bear