EVE General Discussion

EVE numbers are ridiculous. We all know it… yet I decided to do some fun calculations to find out more about XL weaponry and the numbers involved. So for the following ridiculous eve numbers – I have used the Naglfar’s Depleted Uranium XL shells.

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Firstly, this XL shell can come in two sizes.. 3500mm or 2500mm. I will run calculations for both of these sizes.

https://image.eveonline.com/Type/20739_64.png

From the above picture, we can work out the approximate shell size. The base is 5mm in diameter and the height is 15mm. By using that ratio, we find out that the 3500mm shell is 10.5 metres tall and the 2500mm shell is 7.5 metres tall.
Next I’ll work out the volume of each shell. The Problem is, that the cone isn’t perfect and is rather round. Therefore I’ll calculate what a perfect cone would be volume-wise and then add 20%.

The cylindrical section of the 3500mm shell is 7 metres tall, and so has a volume of 67.37m3. The cone section is 3.5 metres tall and so has a volume of 11.22m3, +20% = 13.46m3. Therefore, the total volume of the 3500mm shell is 80.83m3.

The cylindrical section of the 2500mm shell is 5 metres tall and so has a volume of 24.55m3. The cone section is 2.5 metres tall and so has a volume of 4.09m3, +20% = 4.91m3. Therefore the total volume of the 2500mm shell is 29.46m3.

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Now I’d like to work out the weight of each warhead. We don’t know if it is rocket assisted or not, but for the sake of this calculation, I’ll say it isn’t. Therefore we have a 13.46m3 warhead for the 3500mm shell and a 4.91m3 warhead for the 2500mm shell.

Depleted Uranium has a density of 19.1g/cm3. Therefore the 3500mm shell’s warhead weighs 257,086 kg, and the 2500mm shell’s warhead weighs 93,781 kg.

Therefore in a full volley, the Naglfar fires:
With artillery – 2,056,688kg of Depleted Uranium
With autocannons – 1,125,372kg of Depleted Uranium

To put this into perspective, the HMS Amazon, a Destroyer built after WWI, weighed 1,371,663kg. Therefore, the Naglfar fires 1.49 HMS Amazons a volley, with artillery.

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Now, I’d like to work out the potential energy of each warhead as well. Again, we don’t know the muzzle velocity of the Naglfar’s weaponry so this is an estimation. Modern tank cannons get muzzle velocities of around 1700m/s, therefore I’ll use that as a benchmark for the following calculations. I do believe this will be lower than it should be considering ‘future’ tech in the EVE universe, but it is close enough.

For the 3500mm shell firing 257,086kg at 1700m/s, the energy it releases per shot is the same as 88.8 tons of TNT. This equates to a full Naglfar volley power of 710.4 tons of TNT.

For the 2500mm shell firing 93,781kg at 1700m/s, the energy it releases per shot is the same as 32.4 tons of TNT. This equates to a full Naglfar volley power of 388.8 tons of TNT.

To put that in perspective, the largest conventional weapon made by man, the Russian, “Father of All Bombs’, has a yield of 44 tons of TNT. So the Naglfar fires 16.1 FOAB’s worth of energy every volley, with artillery.

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Some very interesting numbers in all of the above calculations and it really makes you think. The one thing that sticks on my mind is the fact that the Naglfar can throw out more than a destroyer every volley and yet that doesn’t instantly kill everything it touches.

What do you think?

Why didn't you use a smaller picture?

The velocity of projectiles in EVE is 250km in 1s.

Except in space, those are masses, not weights.

Uh, that was 44 million tons. That big M means 'million'.

Ah I confused that with the tsar bomba.

Russians still have a bigger boom stick

Uhrm no. Someone kindly rolled a Herpes corp and spammed a load of MD posters a few years back with shares. Don't tell anyone. Think I got two shares :|

wrong thread

Also known as TiDi.