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Real Talk: Temperate Planets
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Proclus Diadochu
Mar Sarrim
Red Coat Conspiracy
#1 - 2013-12-14 10:17:10 UTC
Could you verify that all the temperate planets in New Eden are actually in the Goldilocks zone?


This is messing with my immersion.

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Ramona McCandless
Silent Vale
LinkNet
#2 - 2013-12-14 10:20:07 UTC
Why do they have to be?

You would need to cite the spectral class of the star or stars in the system you wish to survey.

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baltec1
Bat Country
Pandemic Horde
#3 - 2013-12-14 10:23:18 UTC
A blue planet that rains diamonds horizontally. Sun cream is advisable.
WASPY69
Xerum.
#4 - 2013-12-14 12:07:54 UTC
The way you usually calculate this zone is somewhat simple actually! Since every star in EVE provides the necessary info! =D

We do it in a few steps

Ri = Sqrt( Lstar / 1.1 )

and then

Ro = Sqrt( Lstar / 0.53 )

where Ri = the inner boundary of the habitable zone in astronomical units (AU), and Ro is the same but the outer boundary.
Lstar is the absolute luminosity of the star. 1.1 is a constant value representing stellar flux at the inner radius, and 0.53 like above represents the outer part.
So just click info on any given star and calculate away!

For example, the sun in the 6-CZ49 system in EVE the sun has a Luminosity of 0.14, which means:

Ri = Sqrt( 0.14 / 1.1 ) which equals to an inner habitable zone radius of 0.35 AU from the star, and then
Ro = Sqrt( 0.14 / 0.53 ) which equals to an outer habitable zone radius of 0.5 AU from the star.

To prove these calculations, input the same info using our very own star and you will get a delightful confirmation that the earth is indeed within the Goldilocks zone.

Furthermore there are other determinating factors. Such as the atmosphere of said temperate planet. If the atmosphere is several times thicker than the Earths atmosphere it would have a big greenhouse effect thus causing the temperature to be within the liquid water range.
Also nuclear decay from the planet itself would cause sufficient background radiation to support liquid water and an atmosphere.
Point being it IS possible for a planet to be outside the Goldilocks zone and still be habitable.

This signature intentionally left blank
Vincent Athena
Photosynth
#5 - 2013-12-14 15:12:10 UTC
Eve planets are all over the place. Ice planets where there can be no ice, temperate planets in wild locations. Sure there can be "special cases" but in eve most every system is "Special".

Also there are issues like the star in Luminaire is 30 billion years old. Which is sort of hard to have in a 13.7 billion year old universe. And no, its not clue to something odd. When I was in the AJ project I checked with CCP Dropbear. Its just a mistake.

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Amber Kurvora
#6 - 2013-12-14 15:19:56 UTC
It's almost like it's a computer game where you're supposed to enjoy shooting things, and not worry about the scientific accuracy... Next up you'll be asking CCP to prove the biomechancial mechanism and software that allows the implants to interface with the human brain.
Bel Tika
Sebiestor Tribe
Minmatar Republic
#7 - 2013-12-14 15:21:32 UTC
huh there is planets in this game? all i ever see is rocks and they speak to me
ElQuirko
University of Caille
Gallente Federation
#8 - 2013-12-14 16:37:40 UTC
WASPY69 wrote:
The way you usually calculate this zone is somewhat simple actually! Since every star in EVE provides the necessary info! =D

We do it in a few steps

Ri = Sqrt( Lstar / 1.1 )

and then

Ro = Sqrt( Lstar / 0.53 )

where Ri = the inner boundary of the habitable zone in astronomical units (AU), and Ro is the same but the outer boundary.
Lstar is the absolute luminosity of the star. 1.1 is a constant value representing stellar flux at the inner radius, and 0.53 like above represents the outer part.
So just click info on any given star and calculate away!

For example, the sun in the 6-CZ49 system in EVE the sun has a Luminosity of 0.14, which means:

Ri = Sqrt( 0.14 / 1.1 ) which equals to an inner habitable zone radius of 0.35 AU from the star, and then
Ro = Sqrt( 0.14 / 0.53 ) which equals to an outer habitable zone radius of 0.5 AU from the star.

To prove these calculations, input the same info using our very own star and you will get a delightful confirmation that the earth is indeed within the Goldilocks zone.

Furthermore there are other determinating factors. Such as the atmosphere of said temperate planet. If the atmosphere is several times thicker than the Earths atmosphere it would have a big greenhouse effect thus causing the temperature to be within the liquid water range.
Also nuclear decay from the planet itself would cause sufficient background radiation to support liquid water and an atmosphere.
Point being it IS possible for a planet to be outside the Goldilocks zone and still be habitable.

This was the most science thing I read today. Kudos.

Dodixie > Hek
Remiel Pollard
Aliastra
Gallente Federation
#9 - 2013-12-14 16:56:52 UTC
WASPY69 wrote:
The way you usually calculate this zone is somewhat simple actually! Since every star in EVE provides the necessary info! =D

We do it in a few steps

Ri = Sqrt( Lstar / 1.1 )

and then

Ro = Sqrt( Lstar / 0.53 )

where Ri = the inner boundary of the habitable zone in astronomical units (AU), and Ro is the same but the outer boundary.
Lstar is the absolute luminosity of the star. 1.1 is a constant value representing stellar flux at the inner radius, and 0.53 like above represents the outer part.
So just click info on any given star and calculate away!

For example, the sun in the 6-CZ49 system in EVE the sun has a Luminosity of 0.14, which means:

Ri = Sqrt( 0.14 / 1.1 ) which equals to an inner habitable zone radius of 0.35 AU from the star, and then
Ro = Sqrt( 0.14 / 0.53 ) which equals to an outer habitable zone radius of 0.5 AU from the star.

To prove these calculations, input the same info using our very own star and you will get a delightful confirmation that the earth is indeed within the Goldilocks zone.

Furthermore there are other determinating factors. Such as the atmosphere of said temperate planet. If the atmosphere is several times thicker than the Earths atmosphere it would have a big greenhouse effect thus causing the temperature to be within the liquid water range.
Also nuclear decay from the planet itself would cause sufficient background radiation to support liquid water and an atmosphere.
Point being it IS possible for a planet to be outside the Goldilocks zone and still be habitable.


The real question is...

Is it possible for that planet to be closer to the sun than the GZ and still be habitable? Blink

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Jandice Ymladris
Aurora Arcology
#10 - 2013-12-14 17:21:01 UTC
Remiel Pollard wrote:
[
The real question is...

Is it possible for that planet to be closer to the sun than the GZ and still be habitable? Blink


It would be hard (on high luminosity stars it could be easier, on low ones alot harder due to the tidal lock that will happen at such short distances), but considering what freaky exoplanets we discover every other week, I wouldn't rule it out.

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WASPY69
Xerum.
#11 - 2013-12-14 17:26:05 UTC
Jandice Ymladris wrote:
Remiel Pollard wrote:
[
The real question is...

Is it possible for that planet to be closer to the sun than the GZ and still be habitable? Blink


It would be hard (on high luminosity stars it could be easier, on low ones alot harder due to the tidal lock that will happen at such short distances), but considering what freaky exoplanets we discover every other week, I wouldn't rule it out.

Well let's just say it's not impossible, just very very, very unlikely. Look at Venus for example, there's signs it may have had water in the past, but it's atmosphere, consisting of 96% or something CO2 is basically a greenhouse effect gone out of control causing the temperature to evaporate all the water.
So "habitable" is all relative. Perhaps habitable for micro organisms living deep inside the crust or something.

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Proclus Diadochu
Mar Sarrim
Red Coat Conspiracy
#12 - 2013-12-14 18:48:33 UTC
This is a solid discussion, but I posted this like 8 hours ago, and CCP still hasn't fixed this "issue".


Now I want the Ice planets on the backend of the GZ.

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Forum Clone 77777
Doomheim
#13 - 2013-12-14 19:18:42 UTC
As stupid and useless as this thread is, its unfortunately not the first of its kind..
Proclus Diadochu
Mar Sarrim
Red Coat Conspiracy
#14 - 2013-12-14 19:23:18 UTC
As stupid and useless as your opinion is, its unfortunately not the first of its kind..

Minister of High Society | Twitter: @autoritare

E-mail: diogenes.proc@gmail.com

My Blog: http://diogenes-club.blogspot.com/

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Xuixien
Solar Winds Security Solutions
#15 - 2013-12-14 19:25:15 UTC
Remiel Pollard wrote:
WASPY69 wrote:
The way you usually calculate this zone is somewhat simple actually! Since every star in EVE provides the necessary info! =D

We do it in a few steps

Ri = Sqrt( Lstar / 1.1 )

and then

Ro = Sqrt( Lstar / 0.53 )

where Ri = the inner boundary of the habitable zone in astronomical units (AU), and Ro is the same but the outer boundary.
Lstar is the absolute luminosity of the star. 1.1 is a constant value representing stellar flux at the inner radius, and 0.53 like above represents the outer part.
So just click info on any given star and calculate away!

For example, the sun in the 6-CZ49 system in EVE the sun has a Luminosity of 0.14, which means:

Ri = Sqrt( 0.14 / 1.1 ) which equals to an inner habitable zone radius of 0.35 AU from the star, and then
Ro = Sqrt( 0.14 / 0.53 ) which equals to an outer habitable zone radius of 0.5 AU from the star.

To prove these calculations, input the same info using our very own star and you will get a delightful confirmation that the earth is indeed within the Goldilocks zone.

Furthermore there are other determinating factors. Such as the atmosphere of said temperate planet. If the atmosphere is several times thicker than the Earths atmosphere it would have a big greenhouse effect thus causing the temperature to be within the liquid water range.
Also nuclear decay from the planet itself would cause sufficient background radiation to support liquid water and an atmosphere.
Point being it IS possible for a planet to be outside the Goldilocks zone and still be habitable.


The real question is...

Is it possible for that planet to be closer to the sun than the GZ and still be habitable? Blink


It's easier for a planet to warm itself up than cool itself off.

For example, one of the moons of Jupiter is thought to have liquid water under it's icy surface that could sustain life.

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Dont UseYourAlt OnTheForums
Doomheim
#16 - 2013-12-14 19:29:12 UTC
Everything is possible.

/thread
NEONOVUS
Mindstar Technology
Goonswarm Federation
#17 - 2013-12-15 00:39:14 UTC
Bel Tika wrote:
huh there is planets in this game? all i ever see is rocks and they speak to me

I've had that happen.
Fascinating what you can do with quartz crystals.
Tavi Baldocchi
Federal Navy Academy
Gallente Federation
#18 - 2013-12-15 05:19:59 UTC
EVE IS REAL
James Amril-Kesh
Viziam
Amarr Empire
#19 - 2013-12-15 07:27:11 UTC
Considering planets don't actually orbit and that many stars are impossibly old (like hundreds of billions of years) I wouldn't count on them having that kind of attention to detail.

Enjoying the rain today? ;)
James Amril-Kesh
Viziam
Amarr Empire
#20 - 2013-12-15 07:28:38 UTC  |  Edited by: James Amril-Kesh
Xuixien wrote:
For example, one of the moons of Jupiter is thought to have liquid water under it's icy surface that could sustain life.

Yep, that would be Europa.

Venus is also much, much hotter than Mercury owing to its extremely thick and CO2 rich atmosphere, despite Mercury being much closer to the sun.

Enjoying the rain today? ;)
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