My EVE

Hello everyone.

I asked myself the same question and I decided to find a solution for this (because I couldn't find an answer after spending some time with google). With Gaussian Elimination I figured out how many ores you need in total to be able to build a ship, a weapon, a component etc.

I used Evelopedia to pick out the 7 ores which gives the best yield for each mineral. These are:

Veldspar (Tritanium)
Scordite (Pyerite)
Plagioclase (Mexallon)
Omber (Isogen)
Hemorphite (Nocxium)
Crokite (Zydrine)
Arkonor (Megacyte)

Some forumulas may become quite complicated, so I use values where you can figure it out yourself how I came up with it (use evelopedia for help). The solution of each formula shows the numbers of cycles needed, not the amount of ores. In most cases you need to round up the results. Do this after you calculated each value, not within the process.
So lets get it started:

Arkonor:

Arkonor is pretty easy because it's the only ore from the chosen 7 where you can get Megacyte.

Arkonor = Megacyte/333


Crokite:

Crokite is the most complicated formula of all. It depends not just on the amount of Zydrine and Arkonor but on the amount of Nocxium as well.

Crokite = (Zydrine - 28*Nocxium/424 - 166*Arkonor) / (663 - 28*331/424)


Hemorphite:

Hemorphite = (Nocxium - 331*Crokite) / 424


Omber:

Omber = (Isogen - 212*Hemorphite) / 307


Plagioclase:

Plagioclase is the only ore of the chosen 7 with Mexallon (similar to Arkonor with Megacyte)

Plagioclase = Mexallon / 256


Scordite:

Scordite = (Pyerite - 512*Plagioclase - 123*Omber) / 416


Veldspar:

Tritanium can be found in all ores of the chosen 7. The forumla is quite long for Veldspar. Thanks to resource rebalancing in Odyssey there are 2 versions to calculate the amount of Veldspar:

Before Odyssey
Veldspar = (Tritanium - 833*Scordite - 256*Plagioclase - 307*Omber - 212*Hemorphite - 331*Crokite - 300*Arkonor) / 1000

Since Odyssey
Veldspar = (Tritanium - 833*Scordite - 256*Plagioclase - 307*Omber - 212*Hemorphite - 38000*Crokite - 10000*Arkonor) / 1000



Quite much, isn't it. I think it's best to use this with an example with a Raven Blueprint

Arkonor = 2479 / 333 = 7.4444
Crokite = (7766 - 28*32555/424 - 166*7.4444) / (663 - 28*331/424) = 6.8321
Hemorphite = (32555 - 331*6.8321) / 424 = 71.4471
Omber = (130371 - 212*71.4471) / 307 = 375.3232
Plagioclase = 522143/256 = 2039.6211
Scordite = (2084282 - 512*2039.6211 - 123*375.3232) / 416 = 2389.0174

Veldspar_old = 5688.3347
Veldspar_new = 5358.764


Therefore we have the following values from cycles to necessary amount:

Veldspar = 5,689 (old) and 5,359 (new) => 1,894,437 (old) and 1,784,547 (new)
Scordite = 2,390 => 795,870
Plagioclase = 2,040 => 679,320
Omber = 376 => 188,000
Hemorphite = 72 => 36,000
Crokite = 7 => 1,750
Arkonor = 8 => 1,600


Using integers instead of floats you get the following results:

Veldspar = 5,689 (old) and 5,347 (new) => 1,894,437 (old) and 1,780,551 (new)
Scordite = 2,389 => 795,537
Plagioclase = 2,040 => 679,320
Omber = 375 => 187,500
Hemorphite = 72 => 36,000
Crokite = 7 => 1,750
Arkonor = 8 => 1,600

Not much difference, but as you can see in this example you need less Veldspar, Scordite and Omber when using integers.
I really believe that this will help many players which specialised themselves in mining and manufactoring.