EVE New Citizens Q&A

I have only been playing a few days but I was curious about mining times. So I know for instance if I am mining with the venture I can get:
Omber 8,333 units
Veldspar 50,000 units

However they both worth out to that 5,000m3

Now my question is the time, does it take the same amount of time to get both of those amounts or are they different?

The time to fill the Ore Hold will always be the same. (Barring Skill/fit changes)

Not all Ore's take up the same space.

lasers/miners mine every ore at the same speed

if i remember correctly my venture mined like 180 cubic meters per minute per laser regardless of ore type

i guess they really weren't exaggerating when they said there's a shortage of maths teachers.

Every ore has it's own volume 0.1m3, 0.35m3, 0.30m3 and so on. Your lasers will mine in m3. So it depends on how big the volume of 1 unit of that ore will be. 100 m3 = 1000 units of 0.1m3 volume ore. Your m3 per cycle will increase with different mining lasers and better skills.

Mining yield is always based on cubic meters.

A T2 Mining Laser took in, last I checked (which was several years ago), 60 cubic meters per minut.

Veldspar is 0.1 cubic meters per unit, so 60 cubic meters of Veldspar is the same as 600 units of Veldspar.

Omber is 0.6 cubic meters per unit, so 60 cubic meters of Omber is the same as 100 units of Omber.

All ores that can occur in high-sec are worth roughly the same per cubic meters. I think Hedbergite, the most valuable high-sec ore (you can find it if you scan for Gravimetric sites) is worth about 50% more than Omber, the least valuable ore type, so it's a very narrow span.

If you look at Market values, though, you'll see that Veldspar is worth little and, e.g., Kernite is worth a lot, but that's because when you're in the Market, you buy and sell units, not cubic meters.

The formula isn't that hard:


Cycle time: x seconds.
Amount mined: y m3 (yes, you mine a set amount of m3 each cycle, not a set amount of units).
Size of ore: z m3

The first 2 are found by right clicking your miner on the venture and select "show info" and go to the attributes tab.
The last one is found by right clicking any ore and select "show info" and go to the attributes tab.

Now say for instance:

x = 120 seconds

y = 400 m3

z = 0.1 m3

Now what does this mean:

Your yield each cycle will be 200 m3 (y)
It takes a certain amount of time to complete this cycle, in this case 2 minutes = 120 seconds (x)

You are mining an ore that has a size of 0.1 m3 (z)

This means at the end of each cycle you get:

amount of ore mined = x / z = 400 / 0.1 = 4000 units.
This is known as yield in units.

Your mining speed will be:

yield in units / time = (x / z) / y

In this example: (400 / 0.1) / 120 = 33.333 units / second = 2000 units / minute.

The same can be done for yield in m3.

yield in m3 = x / y

In this example: 400 / 120 = 3.333 m3 / second = 200 m3 / minute.